8y^2=2y^-1

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Solution for 8y^2=2y^-1 equation: 



8y^2=2y^-1

We move all terms to the left:

8y^2-(2y^-1)=0

We get rid of parentheses

8y^2-2y^+1=0

We add all the numbers together, and all the variables

8y^2-2y+1=0

a = 8; b = -2; c = +1;
Δ = b2-4ac
Δ = -22-4·8·1
Δ = -28
Delta is less than zero, so there is no solution for the equation

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